2(b^2-8)=2b(b+4)

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Solution for 2(b^2-8)=2b(b+4) equation:


Simplifying
2(b2 + -8) = 2b(b + 4)

Reorder the terms:
2(-8 + b2) = 2b(b + 4)
(-8 * 2 + b2 * 2) = 2b(b + 4)
(-16 + 2b2) = 2b(b + 4)

Reorder the terms:
-16 + 2b2 = 2b(4 + b)
-16 + 2b2 = (4 * 2b + b * 2b)
-16 + 2b2 = (8b + 2b2)

Add '-2b2' to each side of the equation.
-16 + 2b2 + -2b2 = 8b + 2b2 + -2b2

Combine like terms: 2b2 + -2b2 = 0
-16 + 0 = 8b + 2b2 + -2b2
-16 = 8b + 2b2 + -2b2

Combine like terms: 2b2 + -2b2 = 0
-16 = 8b + 0
-16 = 8b

Solving
-16 = 8b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-8b' to each side of the equation.
-16 + -8b = 8b + -8b

Combine like terms: 8b + -8b = 0
-16 + -8b = 0

Add '16' to each side of the equation.
-16 + 16 + -8b = 0 + 16

Combine like terms: -16 + 16 = 0
0 + -8b = 0 + 16
-8b = 0 + 16

Combine like terms: 0 + 16 = 16
-8b = 16

Divide each side by '-8'.
b = -2

Simplifying
b = -2

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